How to Find i2 in Complex Circuit?

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We the circuit that I have attached in the post.I have to find i1 and i2. So,to find i,I have to find the equivalent resistance and then divide the voltage by the resistance and find the current.So i take the resistances 15 Ohm and 10 Ohm like they are in parallel and 8 Ohm and 24 Ohm like they are in parallel too.I add this one to the 24 Ohm on the right.Then I take this and the (10 ||15) in parallel.I add the little 3 Ohm.Then we have an equivalent 8 Ohm.SO i1=8 Ohm.Awesoome.The problem is ,how to find i2 now?
Note : If it is not clear in the figure,i1 is near 3 Ohm and i2 is near 15 Ohm.
 

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If you know i1, then you know the drop across the 3Ω resistor...
 
And how would that help me?
 
Elaia06 said:
And how would that help me?

It helps because you can find the potential drop across the 3Ω resistor.
 
Hehe,I get it,but how would finding that potential help me find i2? Give me a little hint :)
 
Elaia06 said:
Hehe,I get it,but how would finding that potential help me find i2? Give me a little hint :)

What else is connected to the other end of that resistor?
 
I don't get this.However,thank you.
 
Take a look at this diagram:
attachment.php?attachmentid=57890&stc=1&d=1366055301.gif

You can find the potential drop V1 across the 3Ω resistor. So what's the potential of node A with respect to the reference node?
 

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16 Volt?
 
  • #10
Elaia06 said:
16 Volt?
Can you show your calculation?
 
  • #11
To be honest,I guessed it.I have learned the kirchhoffs laws and applied them many times,but I don't know how to apply it here.
 
  • #12
Elaia06 said:
To be honest,I guessed it.I have learned the kirchhoffs laws and applied them many times,but I don't know how to apply it here.

That's why I asked :smile:

What potential drop did you find for V1 (across the 3Ω resistor)? Do a "KVL walk" from the reference node, up through the voltage source, through the resistor to node A, summing the potential changes.
 

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