Are These Probability Calculations Correct?

  • Context: Undergrad 
  • Thread starter Thread starter tronter
  • Start date Start date
  • Tags Tags
    Probability
Click For Summary

Discussion Overview

The discussion revolves around the correctness of various probability calculations related to stopping at traffic light signals. Participants analyze the probabilities associated with stopping at one or both signals, exploring the implications of independence and conditional probabilities.

Discussion Character

  • Technical explanation, Debate/contested, Mathematical reasoning

Main Points Raised

  • One participant presents a series of probability calculations regarding stopping at traffic signals, including P(A), P(B), and P(A ∩ B).
  • Another participant agrees with the initial calculations but requests clarification on the calculation for stopping at the first signal but not the second.
  • A different participant challenges the calculation for stopping at the first signal but not the second, asserting it should be calculated as P(A) - P(A ∩ B).
  • Another participant reiterates the challenge to the calculation and suggests that if the events are independent, it should be calculated as P(A) * (1 - P(B)).

Areas of Agreement / Disagreement

Participants express disagreement regarding the calculation of the probability of stopping at the first signal but not the second, with multiple competing views on the correct approach.

Contextual Notes

There is an assumption of independence in one of the proposed calculations, but this has not been universally accepted or clarified among participants.

tronter
Messages
183
Reaction score
1
P(\text{stop at first light signal}) = 0.4 = P(A)

P(\text{stop at second light signal}) = 0.5 = P(B)

P(\text{stop at least one of two signals}) = 0.6 = P(A \cup B)

Then P(A \cap B) = P(A) + P(B) - P(A \cup B) = 0.3

P( \text{first signal but not second}) = P(A \cap B') = 1-0.3 = 0.7

P(\text{exactly one signal}) = P(A \cup B) - P(A \cap B) = P(A \Delta B) = 0.3


Are these correct?
 
Physics news on Phys.org
They are; except can you explain P(1st but not 2nd) = 0.7?
 
yeah that's incorrect. It should be P(A \cap B') = P(A) - P(A \cap B) = 0.4-0.3 = 0.1
 
tronter said:
yeah that's incorrect. It should be P(A \cap B') = P(A) - P(A \cap B) = 0.4-0.3 = 0.1
Shouldn't it be P(A \cap B') = P(A) * (1-P(B))

Assuming there independent
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 36 ·
2
Replies
36
Views
5K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
10
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 29 ·
Replies
29
Views
6K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 7 ·
Replies
7
Views
1K
  • · Replies 9 ·
Replies
9
Views
2K