Are Z21 and C2*C6 Isomorphic?

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Discussion Overview

The discussion revolves around the isomorphism between the group of units of \(\mathbb{Z}_{21}\) and the direct product of cyclic groups \(\mathbb{C}_2 \times \mathbb{C}_6\). Participants explore methods to demonstrate this isomorphism, including examining the structure of the groups involved and proving properties related to cyclic groups.

Discussion Character

  • Exploratory
  • Technical explanation
  • Homework-related

Main Points Raised

  • One participant questions how to show that the units of \(\mathbb{Z}_{21}\) are isomorphic to \(\mathbb{C}_2 \times \mathbb{C}_6\) and mentions discrepancies in their multiplicative tables.
  • Another participant suggests starting by proving that \(\mathbb{Z}_{21} \simeq \mathbb{Z}_3 \times \mathbb{Z}_7\) and highlights the importance of the GCD condition.
  • A participant expresses difficulty in proving the earlier suggestion, acknowledging the GCD condition but seeking further assistance.
  • Another reply encourages proving that the group on the right is cyclic.
  • A participant expresses frustration with their progress, indicating a challenging day.
  • One participant proposes a method to show that every element of \(\mathbb{Z}_3 \times \mathbb{Z}_7\) can be expressed in a specific form, referencing the Chinese Remainder Theorem as a helpful resource.

Areas of Agreement / Disagreement

Participants do not appear to reach a consensus on the methods to prove the isomorphism, with some expressing uncertainty and seeking further clarification. Multiple competing views and approaches remain in the discussion.

Contextual Notes

Limitations include the participants' varying levels of understanding regarding cyclic groups and the application of the Chinese Remainder Theorem, as well as unresolved steps in proving the necessary properties of the groups involved.

razorg425
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Hi guys just a quick question on how I would go about showing the units of Z21 is isomorphic toC2*C6(cyclic groups).I have done out the multiplicative table but they seem to be different to me. What else can I do?
 
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Start by proving that [tex]\mathbb{Z}_{21} \simeq \mathbb{Z}_3 \times \mathbb{Z}_7[/tex]. What are the groups of units of [tex]\mathbb{Z}_3[/tex] and [tex]\mathbb{Z}_7[/tex]?

(Hint: it's important that GCD(3,7)=1.)
 
Sorry Rochfor,
I actually can't prove that, I know it should be true as gcd(3,7)=1.
A little more help please?
Thanks.
 
Try proving that the group on the right is cyclic.
 
Jeez i can't even do that.
Im having a terrible day with this.
 
So we want to show that every element of [tex]\mathbb{Z}_3 \times \mathbb{Z}_7[/tex] is of the form [tex]n \cdot ( [1]_3, [1]_7 )[/tex]. So for [tex]x, y \in \mathbb{Z}[/tex], we want [tex]( [x]_3, [y]_7 ) = n \cdot ( [1]_3, [1]_7 ) = ( [n]_3, [n]_7 )[/tex]. So we need to find a number n so that [tex]x \equiv n \mod 3[/tex] and [tex]y \equiv n \mod 7[/tex]. The http://mathworld.wolfram.com/ChineseRemainderTheorem.html" is your friend.
 
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