Area of a Segment of a Circle, when only the radius is known.

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SUMMARY

The discussion focuses on calculating the area of a segment of a circle with a radius of 2, where the angle is determined through geometric relationships. The participants clarify that the angle AOD is 60 degrees, derived from the properties of triangle AOD, where OD is 1 and AD is √3. The formula for the area of the segment is established as A = πr²(θ/360) - 0.5r²sin(θ), with θ being 60 degrees. The final area can be expressed in terms of surds and π.

PREREQUISITES
  • Understanding of circle geometry and properties of segments
  • Familiarity with trigonometric functions and their applications
  • Knowledge of the formula for the area of a segment of a circle
  • Basic skills in solving right-angled triangles
NEXT STEPS
  • Study the derivation of the area of a segment of a circle using different angles
  • Learn about the properties of triangles, particularly right-angled triangles
  • Explore the relationship between angles and arc lengths in circles
  • Practice problems involving the calculation of areas of segments with varying radii and angles
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Students of geometry, mathematics educators, and anyone interested in advanced circle properties and segment area calculations.

malam1990
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A circle has Centre 0 and radius 2. A, B and C are points on the circumference of a circle such that AB is the perpindicular bisector of 0C.

Find the area of the segment of the circle bounded by the line segment AB and the minor arc ACB.

Give the area in exact forms in terms of surds and pi.

I have uploaded the circle diagram as well.

I understand how to find the area of a segment of a circle when I know the angle and radius, but am unsure when I only know the radius. Any help will be greatly appreciated!

Cheers
 

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Well show me how you would do it if you knew the angle
 
I would use the formula:

A = \Pir2\theta/360 - 0.5r2sin\theta



cheers
 
hi malam1990! :smile:

(have a theta: θ :wink:)
malam1990 said:
A circle has Centre 0 and radius 2. A, B and C are points on the circumference of a circle such that AB is the perpindicular bisector of 0C.

I understand how to find the area of a segment of a circle when I know the angle and radius, but am unsure when I only know the radius.

but you do know the angle …

you know the lengths of two sides of triangle AOD (where D bisects AB) :wink:
 
OC, OA, and OB are all radii of the circle, right?
 
tiny-tim said:
hi malam1990! :smile:

(have a theta: θ :wink:)


but you do know the angle …

you know the lengths of two sides of triangle AOD (where D bisects AB) :wink:


Hi, thanks for the help, but I'm still not sure how I get to know the angle, the answer is probably really obvious but unfortunately I am just not seeing it. So far I have θ as 90 degress but am unsure whether this is correct.

Cheers for the help again! it is much appreciated!
 
SammyS said:
OC, OA, and OB are all radii of the circle, right?

yes they are.

cheers for any help.
 
hi malam1990! :smile:
tiny-tim said:
you know the lengths of two sides of triangle AOD (where D bisects AB) :wink:
malam1990 said:
Hi, thanks for the help, but I'm still not sure how I get to know the angle …

what are the lengths of two sides of triangle AOD ? :wink:
 
tiny-tim said:
hi malam1990! :smile:



what are the lengths of two sides of triangle AOD ? :wink:

well I know OA is 2 as it is the radius, but I am still unsure how I would get to know either OD or DA?

cheers
 
  • #10
but you know that D is the bisector of OC :wink:
 
  • #11
tiny-tim said:
but you know that D is the bisector of OC :wink:

I'm really sorry but I'm still not getting it, I can't see how it helps me know definitely the length of one of the other sides of the traingle AOD. :confused:
 
  • #12
SammyS said:
OC, OA, and OB are all radii of the circle, right?

Therefore, AB bisects OC.

That should let you find the angle!
 
  • #13
Would I be correct in thinking that OD would be 1 and AD being \sqrt{}3 ?

which would then give me 60deg for the angle AOD? and 120 deg for the angle of the whole sector AOB?
 
  • #14
yup! … AB bisects OC, so OD = OC/2 = 1, so the right-angled triangle has sides 2 1 and √3, and cosAOD = 1/2, so AOD = 60° :smile:
 
  • #15
tiny-tim said:
yup! … AB bisects OC, so OD = OC/2 = 1, so the right-angled triangle has sides 2 1 and √3, and cosAOD = 1/2, so AOD = 60° :smile:

thank you so much for guiding me to finally seeing how to do it!

thanks again! you really have helped me out!
 

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