Area of the Circle and Probability

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Discussion Overview

The discussion revolves around a probabilistic approach to proving the area of a circle as pi*r^2. Participants explore the relationship between the area of a circle and the area of a square through random selection of points within defined bounds, questioning the broader implications of this method in geometry.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification

Main Points Raised

  • One participant proposes a probabilistic argument for the area of a circle, relating it to the area of a square and suggesting that the method could be a special case of a deeper result.
  • Another participant notes that areas of similar figures are proportional to the square of the ratio of their linear dimensions, emphasizing that the challenge lies in evaluating pi.
  • A third participant expresses curiosity about the relevance of the proposed method to geometry and seeks insights on its potential generalizations.
  • A later reply identifies the method as a "Monte Carlo" method, indicating its established presence in mathematics.

Areas of Agreement / Disagreement

Participants generally agree on the validity of the probabilistic approach to understanding the area of a circle, but there is no consensus on the broader implications or potential generalizations of this method.

Contextual Notes

The discussion does not resolve the question of whether the proposed method can yield more fruitful results in geometry, nor does it clarify the evaluation of pi as a constant.

Who May Find This Useful

This discussion may be of interest to those exploring geometric proofs, probabilistic methods in mathematics, or the Monte Carlo technique.

musicheck
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(Apologies for the lack of latex)
I was thinking today about simple ways of proving that the area of a circle is pi*r^2, and I came up with the following argument using probability. I googled around for similar arguments, and I found nothing. I am curious if there is a deeper and more general result this could be a special case of, or if there if anyone else knows of something relating to this.

We know that the area of a square of side length r is r^2. Consider the unit circle centered at the origin, and a circle of radius R centered at the origin. We randomly select two numbers N and M from [-1,1], with uniform distribution. The probability that N^2+M^2<=1 is thus the ratio of the area of the unit circle to the area of a square of side length 2. Now we randomly select two numbers N' and M' from [-R,R]. The probability that N'^2+M'^2<=R^2 is the ratio of the area of the circle of radius R to the area of a square of side length 2R. However, our random selection from [-R,R] is the same as a random selection from [-1,1] and then multiplying by R. Thus, we can calculate that N'^2+M'^2<=r^2 has the same probability as N^2+M^2<=1. Thus, the area of a circle of radius R is proportional to the area of a square of side length 2R. It follows that the area of a circle of radius R has area pi*R^2, for some constant pi.
 
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It is an elementary geometry fact that if you have two figures that are similar, the areas are proportional to the square of the ratio of linear dimension. The more difficult problem is the evaluation of pi, not that it is a constant.
 
I agree that this is a very simple fact. What struck me was that I had never thought of this method of proof as very relevant to geometry, and I was wondering if people knew whether this method (or a generalization of it) of attacking a problem can yield something more fruitful.
 
The method you are talking about, more generally called a "MonteCarlo" method is quite well known in mathematics.
 
Thank you very much HallsofIvy. I had heard that name before, but I didn't know what it was. I'm glad to hear that it is well known, and I look forward to finding a book to read about it.
 

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