Area of Triangle ABC: Find the Solution

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ABC is a triangle. AC=4cm; AB=3cm; A=60 degrees.
I need help finding the area of triangle ABC.
 
If you know the lengths of two sides of a triangle (we'll call them \(a\) and \(b\)), and the angle \(\theta\) subtended by the two sides, then the area \(A\) of the triangle is given by:

$$A=\frac{1}{2}ab\sin(\theta)$$

Can you proceed?