Area under force vs displacement graph :D?

AI Thread Summary
The discussion focuses on calculating the final kinetic energy (Kf) at 4 meters using the area under a force vs. displacement graph. The user correctly calculates the work done (W) as 4J by finding the area of a triangle. They then apply the work-energy principle, substituting into the equation W = Kf - Ki, where Kinitial is given as 2J. After solving, they find Kf to be 6J, which is confirmed as correct by other participants. The conversation also emphasizes the importance of proper formatting for units in calculations.
DK_sam
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Homework Statement


Find K at 4m, besides the F.s graph they also give me Kinitial = 2J

Homework Equations


W=F.d and W=Kf- Ki

The Attempt at a Solution


The first thing I did was to find the area under the graph.
1/2(4)(2)=4J W=F.d so that's my work.
Then I replaced that 4J into the other eq W= Kf-Ki
then solved for Kf.
W+Ki=Kf
plugging in values 4j +(2J)=Kf
then 6J=Kf
Is that correct guys? Thanks for your help!
 

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DK_sam said:

Homework Statement


Find K at 4m, besides the F.s graph they also give me Kinitial = 2J

Homework Equations


W=F.d and W=Kf- Ki

The Attempt at a Solution


The first thing I did was to find the area under the graph.
1/2(4)(2)=4J W=F.d so that's my work.
Then I replaced that 4J into the other eq W= Kf-Ki
then solved for Kf.
W+Ki=Kf
plugging in values 4j +(2J)=Kf
then 6J=Kf
Is that correct guys? Thanks for your help!
looks good! Always put a space between the numerical value and the unit, 6 J not 6J.
 
Thank you good sir! I will next time! :D good night!
 

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