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Argue that lim g(x), with x → -1, = -2

  1. Oct 5, 2014 #1
    Hello, everybody!

    The function g: R → R is differentiable in -1, g' (-1) = 2 and g (-1) = -2. Can someone show me (how to argue) that lim g(x), with x → -1, = -2?

    Thanks in advance!
     
  2. jcsd
  3. Oct 5, 2014 #2

    Zondrina

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    If a function is differentiable at a point, then it is continuous there.

    If ##g## is differentiable, then:

    $$\displaystyle \lim_{x -> a} \frac{f(x) - f(a)}{x - a} = f'(a)$$
     
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