Argue that lim g(x), with x → -1, = -2

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SUMMARY

The limit of the function g(x) as x approaches -1 is definitively -2, based on the properties of differentiability. Given that g is differentiable at -1, it follows that g is continuous at that point, which confirms that lim g(x) as x → -1 equals g(-1). With g'(-1) = 2, the derivative at this point further supports the conclusion that the limit is indeed -2.

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Hello, everybody!

The function g: R → R is differentiable in -1, g' (-1) = 2 and g (-1) = -2. Can someone show me (how to argue) that lim g(x), with x → -1, = -2?

Thanks in advance!
 
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If a function is differentiable at a point, then it is continuous there.

If ##g## is differentiable, then:

$$\displaystyle \lim_{x -> a} \frac{f(x) - f(a)}{x - a} = f'(a)$$
 

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