- #1
Kartik.
- 55
- 1
The proof says that -
Let,
Sn= a+(a+d)+(a+2d)+...+(a+(n-2)d)+(a+(n-1)d)----->1
Sn= (a+(n-2)d)+(a+(n-1)d)+...+a+(a+d)+(a+2d)------>2
Now if we have to add such things(1 and 2) how would we do that?
Let,
Sn= a+(a+d)+(a+2d)+...+(a+(n-2)d)+(a+(n-1)d)----->1
Sn= (a+(n-2)d)+(a+(n-1)d)+...+a+(a+d)+(a+2d)------>2
Now if we have to add such things(1 and 2) how would we do that?