Arithmetic Sequence Homework: Find the Sum

Click For Summary
The discussion centers on solving a homework problem involving arithmetic sequences and their sums. The first part successfully derived the formula for the sum of the first n terms of an arithmetic progression. The second part, concerning double arithmetic progressions, posed challenges in establishing a formula for the sum, with participants suggesting the need for an explicit formula for the terms involved. Clarifications were made regarding the expected results when substituting values, particularly for n=2. The conversation emphasizes the importance of correctly interpreting the problem requirements to achieve accurate results.
FeDeX_LaTeX
Science Advisor
Messages
436
Reaction score
13

Homework Statement



This is taken from STEP I 1990, Q4.

(i) The sequence a1, a2, ..., an, ... forms an arithmetic progression. Establish a formula, involving n, a1, and a2, for the sum of the first n terms.

(ii) A sequence b1, b2, ..., bn, ... is called a double arithmetic progression if the sequence of differences, b2 - b1, b3 - b2, ..., bn+1 - bn, ... is an arithmetic progression. Establish a formula, involving n, b1, b2 and b3, for the sum b1 + b2 + ... + bn of the first n terms of such a progression.

(iii) A sequence c1, c2, ..., cn, ... is called a factorial progression if cn+1 - cn = n!d, for some non-zero d and every n ≥ 1. Suppose 1, b2, b3, ... is a double arithmetic progression, and also that b2, b4, b6 and 220 are the first four terms in a factorial progression. Find the sum 1 + b1 + b2 + ... + bn.

Homework Equations



Standard arithmetic progression formulae below

The nth term of an AP: un = a + (n-1)d
The sum of the first n terms of an AP: Sn = (n/2)(a + l) = (n/2)(2a + (n-1)d)

The Attempt at a Solution



I've done (i) quite comfortably and got

\frac{n}{2}((3-n)a_{1} + (n-1)a_{2})

However, (ii) is where I get stuck. By considering the sequence of differences, I've established that

b_n = a + (n-2)d + b_{n-1}

with a = b2 - b1, and d = (b3 - b2) - (b2 - b1). Can anyone guide me on where to go next?
 
Last edited:
Physics news on Phys.org
FeDeX_LaTeX said:
I've done (i) quite comfortably and got

\frac{n}{2}((3-n)a_{1} + (n-1)a_{2})
With n=2, I get a1+a2, but the result should be a2.

Can anyone guide me on where to go next?
An explicit formula for bn could be useful. In your formula, you can express bn-1 in terms of bn-2 and so on, until you reach b1.
 
mfb said:
With n=2, I get a1+a2, but the result should be a2.

Why? We were looking for the sum of the first n terms. With n = 2, that is a1 + a2.

An explicit formula for bn could be useful. In your formula, you can express bn-1 in terms of bn-2 and so on, until you reach b1.

Ah I see, thanks. I will try this and reply if I get the correct result.
 
FeDeX_LaTeX said:
Why? We were looking for the sum of the first n terms. With n = 2, that is a1 + a2.
Yes, you were correct, FeDeX_LaTeX .
 
Oh sorry, I did not see that (a) should be a sum of the first n terms as well.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
4
Views
2K
Replies
3
Views
5K