Arrow Trajectory: 29° and 50 m/s

[bam3211]

An arrow is shot at 29.0° above the horizontal. Its velocity is 50 m/s and it hits the target.

What is the maximum height the arrow will attain?


The target is at the height from which the arrow was shot. How far away is it?

if anyone could give me some tips or steps to solve this problem that would be great

thanks

 

[ShawnD]

An arrow is shot at 29.0° above the horizontal. Its velocity is 50 m/s and it hits the target.

What is the maximum height the arrow will attain?

Vf^2 = Vi^2 + 2ad

The target is at the height from which the arrow was shot. How far away is it?

How long does the arrow stay in the air? Find that time then multiply it by the horizontal component of the arrow's velocity.


For most (all?) of these gravity related problems, your work should start with the vertical component.