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## Homework Statement

An Arrow is shot from an initial velocity of 45 m/s 52 degrees above the horizontal. It lands on a 5 m high roof of a house. The arrow is shot from a height of 1.5 m.

(v) Would it be able to pass over a 50 m high tree located 75 m away?

(vi) What is its' total time of flight?

(vii) How far away is the house?

## Homework Equations

d = vit +1/2at^2

v=d/t

a = vf-vi/t

## The Attempt at a Solution

I've calculated the max height of the arrow; 65.43 m, and the time, 3.6 s.

I don't know how to calculate the horizontal displacement of an object starting 1.5 m off the ground.