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## Homework Statement

Could someone pls clarify if the value of x changes from just Laguerre polynomial to associated one? I am confused about the role of variable x.

## Homework Equations

From what I have learned in the class, I understand that L

^{1}

_{n}(x) = d/dx Ln(x), n = 1, 2, 3...

## The Attempt at a Solution

Because L

_{1}(x) = 1 - x and L

_{2}(x) = 2 - 4x + x2

I did:

L

_{1}

^{1}(x) = d/dx L1(x) = d/dx (1 - x) = -1

L

^{1}

_{2}(x) = d/dx L2(x) = d/dx (2-4x+x2) = 2x - 4 = 2(x - 2)...I wonder if x is a different function of radius in L

_{1}

^{1}(x) (as in 1s orbital) and L

^{1}

_{2}(x) (as in 2s orbital)? I am assuming the orbital polynomial on the basis of node...as in:

L

_{1}

^{1}(x)= 1 because of 0 nodes...hence 1s

L

^{1}

_{2}(x) = 2x -4 because of 1 node...hence 2s