1. The problem statement, all variables and given/known data 2. Relevant equations 3. The attempt at a solution a) The height of the high tide is 4.5 m b) The height of the low tide is 0.25 m c) Period = 12.5 hours k= 360/12.5 = 28.8 amplitude = 2.125 m vertical shift = 2.375 m phase shift = it doesn't look like there is any phase shift (correct if i am wrong please) So the equation is: -2.125 sin(28.8x) + 2.375 Is my equation correct? d) Determine height of tide at 5:00 pm: y= -2.125 sin (28.8x) + 2.375 y= -2.125 sin (28.8(17)) + 2.375 y = -2.125 sin(489.6) +2.375 y = 0.737 m The height of the tide at 5:00 pm is 0.74 m. When would be a better time for the fisherman to come in? If the fisherman comes in to shore at 5:00 p.m. there will be a low tide with a height of 0.74 m. Since sandbars occur at a low tide (I am assuming) it would be best to come in when the tides are high to avoid getting stuck. For example: The fisherman could come in a few hours after 5:00 pm, between 8:00 pm to 11:00 pm, to catch the high tide. Please look over my answers and point out any mistakes :) Thanks.