Astronaut's Apparent Weight in Different Gravitational Fields

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SUMMARY

The apparent weight of a 730-N astronaut varies significantly based on her acceleration and proximity to gravitational fields. When the spaceship accelerates at 2.0g just above the Earth's surface, the astronaut's apparent weight is calculated to be 2200 N. In contrast, when far from any stars or planets, her apparent weight is 1500 N. The key equation used for these calculations is Wapparent = m(g + a), where 'm' is the mass, 'g' is the gravitational acceleration, and 'a' is the additional acceleration due to the spaceship's thrust.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with gravitational force calculations
  • Knowledge of the concept of apparent weight
  • Ability to manipulate equations involving acceleration
NEXT STEPS
  • Study the effects of varying gravitational fields on weight
  • Learn about the principles of rocket thrust and acceleration
  • Explore the concept of normal force in different gravitational contexts
  • Investigate the implications of significant figures in scientific calculations
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Students in physics, aerospace engineers, and anyone interested in the effects of gravity and acceleration on weight in different environments.

sona1177
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Homework Statement


What is the apparent weight of a 730-N astronaut when her spaceship has an acceleration of magnitude 2.0g in the following two situations:

a) just above the surface of the Earth
b) far from any stars or planets




Homework Equations



Wapparent=m(g + a)


The Attempt at a Solution



=2mg=2 * 74.5 * 9.8=1460 N. I guess this would be the answer to part b, away from stars or planets. My book says a) 2200 N and b) 1500 N (accounting for significant figures). But how do I do part a? I don't see the difference between being just above the surface of the Earth and far from any stars or planets.
 
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sona1177 said:

Homework Statement


What is the apparent weight of a 730-N astronaut when her spaceship has an acceleration of magnitude 2.0g in the following two situations:

a) just above the surface of the Earth
b) far from any stars or planets

Homework Equations



Wapparent=m(g + a)

The Attempt at a Solution



=2mg=2 * 74.5 * 9.8=1460 N. I guess this would be the answer to part b, away from stars or planets. My book says a) 2200 N and b) 1500 N (accounting for significant figures). But how do I do part a? I don't see the difference between being just above the surface of the Earth and far from any stars or planets.
Think of two situations: 1) when the astronaut is standing still, not accelerating; and 2) the case where he/she is accelerating at 2g.

Near the earth, in the first case (a = 0) the normal force (from the rocket thrust) must just equal the force of gravity, mg, in order to have 0 acceleration. In order to accelerate at 2g away from the earth, the force must be 2mg over the force required just to stand still.

If far from gravitational fields, the rocket does not have to provide any thrust in order to maintain 0 acceleration. So in order to accelerate at 2g the force just needs to be 2mg (ie 2mg over the force needed to maintain 0 acceleration).

AM
 

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