MHB At what point on the curve is there a tangent line parallel to the line

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To find the point on the curve y = e^x where the tangent line is parallel to y = 2x, equate the derivative of the curve, e^x, with the slope of the line, which is 2. This leads to the equation e^x = 2. Solving for x gives the point where the slopes are equal. Graphing the function confirms that the tangent line at this point is indeed parallel to y = 2x. Thus, the solution involves finding the x-value that satisfies e^x = 2.
tmt1
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At what point on the curve
$$y = e^x$$ is the tangent line parallel to the line

$$y = 2x$$

The derivative of y is

$$\frac{dy}{dx} = e^x$$

But I'm unsure how to proceed from here.
 
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tmt said:
At what point on the curve
$$y = e^x$$ is the tangent line parallel to the line

$$y = 2x$$

The derivative of y is

$$\frac{dy}{dx} = e^x$$

But I'm unsure how to proceed from here.

You need to equate the slope of the exponential function at a point $x$, which is $e^x$ (as you have found) with the slope of the line $y = 2x$, which is $2$. Hence $e^x = 2$, and solve for $x$. Then if you graph that, you will find that the tangent line to $e^x$ at that point $x$ is parallel to $y = 2x$ as they have the same slope :)
 
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