At what point on the curve is there a tangent line parallel to the line

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SUMMARY

The tangent line to the curve defined by the function \(y = e^x\) is parallel to the line \(y = 2x\) when the slope of the curve equals the slope of the line. The derivative of \(y\) is \(\frac{dy}{dx} = e^x\). To find the point of tangency, set \(e^x = 2\) and solve for \(x\). This results in \(x = \ln(2)\), confirming that the tangent line at this point is parallel to the line \(y = 2x\).

PREREQUISITES
  • Understanding of derivatives and slopes in calculus
  • Familiarity with exponential functions, specifically \(e^x\)
  • Knowledge of logarithmic functions, particularly natural logarithms
  • Graphing skills to visualize functions and their tangents
NEXT STEPS
  • Study the properties of exponential functions and their derivatives
  • Learn how to solve equations involving natural logarithms
  • Explore the concept of tangent lines in calculus
  • Practice graphing exponential functions and their tangents
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Students and educators in calculus, mathematicians interested in function analysis, and anyone looking to deepen their understanding of derivatives and tangent lines.

tmt1
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At what point on the curve
$$y = e^x$$ is the tangent line parallel to the line

$$y = 2x$$

The derivative of y is

$$\frac{dy}{dx} = e^x$$

But I'm unsure how to proceed from here.
 
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tmt said:
At what point on the curve
$$y = e^x$$ is the tangent line parallel to the line

$$y = 2x$$

The derivative of y is

$$\frac{dy}{dx} = e^x$$

But I'm unsure how to proceed from here.

You need to equate the slope of the exponential function at a point $x$, which is $e^x$ (as you have found) with the slope of the line $y = 2x$, which is $2$. Hence $e^x = 2$, and solve for $x$. Then if you graph that, you will find that the tangent line to $e^x$ at that point $x$ is parallel to $y = 2x$ as they have the same slope :)
 

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