I was given the equation of a polynomial told to find the derivative. easy enough.(adsbygoogle = window.adsbygoogle || []).push({});

Then asked to give the equation of the tangent line which I've only learned how to get in the form of the question: "find the equation of the tangent line at x="

They gave me the equation of a line parallel to the tangent.

Typically as we've seen these problems thus far its fairly straightforward derive equation for slope of tangent plug x into the original equation to find the y value and typically put in point-slope form. Alternatively i suppose you could find the y-intercept and put in y=mx+b form but,

How in the heck do you find either the y intercept of the tangent line or the x/y points to do that given only the equation of a parallel line?

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# Calc 1 practice exam question -- finding the y intercept of the tangent line

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