At which times will the ball be at a height of 15 meters?

  • Thread starter Thread starter Gdsykes
  • Start date Start date
  • Tags Tags
    Ball Height
Click For Summary
SUMMARY

The problem involves a ball thrown straight upward with an initial velocity of +20 m/s on a planet with a gravitational acceleration of -10 m/s². To determine the times at which the ball reaches a height of 15 meters, the equation D = ViT + ½at² is utilized. By substituting D with 15 meters and applying the quadratic formula, the correct times can be calculated. The solution confirms that the quadratic formula is the appropriate method for solving this physics problem.

PREREQUISITES
  • Understanding of kinematic equations in physics
  • Familiarity with the quadratic formula
  • Basic knowledge of projectile motion
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Practice solving kinematic equations with different initial velocities and accelerations
  • Explore the concept of projectile motion in two dimensions
  • Learn how to derive and apply the quadratic formula in various contexts
  • Investigate the effects of varying gravitational forces on projectile motion
USEFUL FOR

High school physics students, educators teaching kinematics, and anyone interested in understanding projectile motion and its mathematical applications.

Gdsykes
Messages
1
Reaction score
0

Homework Statement



I am in high school physics. This is my problem that I've been trying to work on: A ball is thrown straight upward with a velocity of +20m/sec on a planet where the acceleration due to gravity is -10m/sec². Find the times at which the ball will be at a height of 15 meters.

Homework Equations


Ok, so I started with this equation: D=ViT+½at². I'm not sure if it's the correct one to use, but I'm pretty sure it is...I think I will need to use the quadratic formula: x= -b+-b²-4ac (square root)/2a. Sorry, I don't know how to make a square root symbol or any of the other signs?!?

The Attempt at a Solution



Now, the problem calls for time, so I must need to solve for it. Next, I got this as the possible equation to utilize when it's solved for time: t-v+- v²+f(1/2a)d (square root) / 2(1/2a)
So far, does everything seem to be right, now all I need to do is "plug and chug?" :) Thanks
-Greg
 
Physics news on Phys.org
Just take you equation for D and use the quadratic formula (or some other method) to solve for t when D = 15m. (Note that at t = 0, D = 0)
 
S=ut + 1/2 at^2
it should be used in a straight line motion and uniform acceleration.
 

Similar threads

Find the Height of a Building by dropping a ball from the top
  • · Replies 7 ·
Replies
7
Views
3K
A ball is thrown w/initial speed vi at an angle 𝜃i with the horizontal
  • · Replies 5 ·
Replies
5
Views
2K
Ball launched from a height of 5 meters --- Projectile motion
  • · Replies 12 ·
Replies
12
Views
1K
Solving a Ball Thrown off a Cliff: How Long Does it Take?
  • · Replies 4 ·
Replies
4
Views
2K
Calculating Passing Height of Two Thrown Balls
  • · Replies 1 ·
Replies
1
Views
2K
Find the buildings height for two balls to land @ same time
  • · Replies 1 ·
Replies
1
Views
2K
Needing some help about time of flight of a launched ball/horiz range
  • · Replies 6 ·
Replies
6
Views
3K
Projectile motion: Two Balls and Building
  • · Replies 9 ·
Replies
9
Views
2K
Hard Kinematics problem: Ball thrown into the air
  • · Replies 9 ·
Replies
9
Views
3K
Calculating the distance traveled by a ball
  • · Replies 9 ·
Replies
9
Views
4K