What's not to understand?Said Ahmad said:Homework Statement
Ball A is thrown vertically by speed 40 m/s. After 1 second, Ball B is thrown vertically also by speed 47.5 m/s.
What height from ground will they pass each other? ( g = 10m/s2 )
Homework Equations
s = vt + ½at2
t = v/g
v2 = v02 + 2asThe Attempt at a Solution
Time A to reach the max height is t = v/g = 40/10 = 4 s
I don't understand. Because there is plus of 1 sec for ball B.
The passing height of two thrown balls can be calculated by using the formula: H = (V1^2 sin^2θ)/(2g), where H is the passing height, V1 is the initial velocity of the first ball, θ is the angle at which the balls are thrown, and g is the acceleration due to gravity.
Calculating the passing height of two thrown balls is important in understanding and predicting the trajectory and motion of the balls. It can also be useful in sports such as baseball and softball, where players need to anticipate and catch or hit a thrown ball at a certain height.
The initial velocity of the balls is a key factor in determining the passing height. The higher the initial velocity, the higher the passing height will be. This is because the balls will travel further and stay in the air for a longer time.
Yes, the passing height of two thrown balls can change during flight due to factors such as air resistance, wind, and changes in the initial velocity or angle of the balls. However, the formula for calculating the passing height assumes no external forces acting on the balls.
The angle at which the balls are thrown can greatly affect the passing height. A higher initial angle will result in a higher passing height, while a lower initial angle will result in a lower passing height. This is because the angle determines the vertical component of the initial velocity, which is a major factor in determining the height of the balls' trajectory.