Atom Interaction: Solving T=E^2/4*(M+m)c^2

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SUMMARY

The discussion centers on solving the equation T=E^2/4*(M+m)c^2, where M is 61 amu, m is 1 amu, E is 710 keV, and c is 3*10^8 m/s. The participant attempted direct substitution but arrived at a result of 2.21 eV, which they found confusing due to its small magnitude. The conversation highlights the importance of unit conversion, particularly converting atomic mass units (amu) to kilograms (kg), to ensure accurate calculations in particle physics.

PREREQUISITES
  • Understanding of the equation T=E^2/4*(M+m)c^2
  • Knowledge of unit conversions, specifically from amu to kg
  • Familiarity with energy units, including keV and eV
  • Basic principles of particle physics
NEXT STEPS
  • Study unit conversion methods between atomic mass units and kilograms
  • Learn about energy unit conversions from keV to eV
  • Explore the implications of small energy values in particle interactions
  • Review the principles of relativistic energy-momentum relationships
USEFUL FOR

Students in physics, particularly those studying particle physics or energy calculations, as well as educators seeking to clarify concepts related to energy and mass in relativistic contexts.

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Homework Statement



The problem is attached

Homework Equations



T=E^2/4*(M+m)c^2
M=61amu,
m=1amu
E=710kev
c=3*10^8m/s
I conver amu to kg

The Attempt at a Solution


direct subtitution but the thing that I got the answer which is 2.21eV which is very small and it confused me have I did something wrong or it is true
 

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why no one helped me?
 

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