Attaching a Two-Cell to a Circle

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SUMMARY

The discussion focuses on the computation of the first homology group ##H_1(X; k)## for the space ##X## obtained by attaching a two-cell to the circle ##S^1## via the map ##S^1 \to S^1## defined by ##z \mapsto z^n##. It concludes that the first homology group is isomorphic to the field ##k## when ##n \geq 1##, indicating that the attachment of the two-cell modifies the homology structure of the circle in a specific way. The discussion emphasizes the importance of understanding the implications of the attaching map on the homological properties of the resulting space.

PREREQUISITES
  • Understanding of algebraic topology concepts, specifically homology groups.
  • Familiarity with the fundamental group and its relation to homology.
  • Knowledge of attaching maps and their effects on topological spaces.
  • Basic proficiency in working with fields in algebraic topology.
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  • Study the properties of homology groups in algebraic topology.
  • Learn about the Universal Coefficient Theorem for homology.
  • Explore the concept of CW complexes and their applications in topology.
  • Investigate the implications of different attaching maps on homological structures.
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Mathematicians, particularly those specializing in algebraic topology, graduate students studying topology, and researchers interested in homological algebra.

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Let ##X## be the space obtained from ##S^1## by attaching a two-cell by the map ##S^1 \to S^1##, ##z\mapsto z^n##. For ##k## an arbitrary field, compute the first homology ##H_1(X; k)##.
 
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X is a CW complex with 1 cell each in dimension ##0,1,2.## Call these cells respectively ##a,b,c.## Since the attaching map for ##c## onto the ##1##-skeleton has degree ##n##, we find ##\partial c=nb.## Also, ##\partial b=a-a=0.## So the cellular chain complex with coefficients in ##k## is: ##k\to k\to k,## where the left map is multiplication by ##n## and the second map is zero. In a field, multiplication by a nonzero element is surjective, so the image of the first map is ##k## unless ##n## is divisible by the characteristic of ##k##. Since the kernel of the second map is also ##k##, we find ##H_1(X,k)=k/k=0.##

In the case that ##n## is a multiple of the characteristic of ##k##, then both maps are zero and ##H_1(X,k)=k/0=k.##
 
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