Average Pressure Radiation on Perfectly Absorbing Surface

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rugerts
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Homework Statement


A light source radiates a sinusoidal electromagnetic wave uniformly in all directions. This wave exerts an average pressure p on a perfectly reflecting surface a distance R away from it. What average pressure (in terms of p) would this wave exert on a perfectly absorbing surface that was twice as far from the source?

Homework Equations


pressure radiation of perfect absorber = (Intensity)/(speed of light)

pressure radiation of perfect reflector = (2 * Intensity)/(speed of light)

Intensity = (Power)/(Area)

Surface Area of Sphere = 4*pi*R^2

The Attempt at a Solution


IMG_1143.v2.jpg

Since you probably can't see that, here's an imgur link: https://imgur.com/a/uxltWGV

When I try to do the math, I get that it's a factor of 1/8. But, if I try to reason through it, it seems like 1/4 is a reasonable answer since I'm just doubling a square factor.

Thanks for your time.
 

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haruspex said:
You are doubling the distance factor, which is squared, but you are also getting afactor of 1/2 from the absorption. Where's the puzzle?
The puzzle is that I get an answer of 1/8 and an answer I found online is 1/4.
 
haruspex said:
Please post the link.

http://www.slader.com/textbook/9780321696861-sears-and-zemanskys-university-physics-with-modern-physics-13th-edition/1074/discussion-questions/12/
 
haruspex said:
Please post the link.
?
 
rugerts said:
http://www.slader.com/textbook/9780321696861-sears-and-zemanskys-university-physics-with-modern-physics-13th-edition/1074/discussion-questions/12/
The question discussed at that link considers two perfectly reflecting surfaces. The question in post #1 of this thread compares a reflecting surface with an absorbing one.
 
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