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Thanks.

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- Thread starter Parsifal1
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- #1

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Thanks.

- #2

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I meant add them together and divide by to, not sub in two pgh.

- #3

Mech_Engineer

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http://www.savannahstate.edu/cost/eng-tech/faculty/jayjan2010/jay/hehslidec2.htm

SavannahState.edu said:The pressure will vary from zero at the surface to (r g h) at the bottom of the wall. The pressure distribution (varying linearly with depth) will be as shown in figure above.

The total resultant force per unit length of wall = average pressure x area = pavg x h x 1

Average pressure = (r g h)/2

Therefore, Resultant force = F = (r g h)/2 x h x 1 = 1/2 {r g h2}

The resultant force acts perpendicular to the wall at the centroid of the pressure distribution triangle, at a distance of h/3 from the bottom of the wall.

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