Average Radius of a Unit Cell: Na

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SUMMARY

The average radius of a unit cell for sodium (Na) is calculated to be 1.86 Å, known as the 'metallic radius'. This value is derived from the body-centered cubic (BCC) structure of metallic sodium, where the diagonal of the unit cell is equal to four ionic radii. The formula used is r = \frac{\sqrt{3}a}{4}, where 'a' is the side length of the unit cell. The density of sodium metal is 968 kg/m³, and the unit cell contains two whole atoms, contributing to the overall calculation.

PREREQUISITES
  • Understanding of body-centered cubic (BCC) crystal structures
  • Familiarity with ionic and metallic radii
  • Basic knowledge of crystallography principles
  • Ability to perform calculations involving density and atomic mass
NEXT STEPS
  • Study the properties of different crystal structures, such as face-centered cubic (FCC) and hexagonal close-packed (HCP)
  • Learn about the relationship between atomic radius and crystal density
  • Explore advanced topics in crystallography, including coordination numbers and bonding types
  • Investigate the implications of crystal structure on material properties in metallurgy
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Chemists, materials scientists, and students studying crystallography or solid-state physics will benefit from this discussion, particularly those interested in the properties of metallic elements like sodium.

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What is the average radius for a unit cell, for example, for Na? Is it the average of the ionic radii for the different coordination numbers (weighting each coordination number the same)? Or would it be the covalent radii or something else?
 
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IIRC, metallic sodium is a body-centered cubic (BCC) crystal. The unit cell looks like http://en.wikipedia.org/wiki/File:Lattice_body_centered_cubic.svg" , a cube with side a, with one atom in the middle and the neighboring atoms on the 8 corners.

So the diagonal is 4 radiii in length, so if the side of the unit cube is a you have 4r = \sqrt{a^2+a^2+a^2} = \sqrt{3}a and the radius is r = \frac{\sqrt{3}a}{4}.
There are two whole atoms in a unit cell (one in the middle and 1/8 in each corner), so the unit cell weighs \frac{2*M_{Na}}{N_A} g. The density of sodium metal is 968 kg/m3.

Do the arithmetic and you get a radius of 1.86 Å. That's called the 'metallic radius'.

As you can see, the size of the unit cell depends on the type of unit cell, the type of bonding going on, etc. Pick up a book on crystallography and you'll see it can actually get rather complicated.
 
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