Average Speed? How do I calculate?

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To calculate average speed on a position-time graph, divide total displacement by total time, using the formula (final position - initial position) / (final time - initial time). For a velocity-time graph, average speed can be determined by finding the area under the curve, which involves calculating the areas of triangles above and below the time axis and subtracting the area below from the area above. This method accounts for negative velocities when the object moves backward. Overall, understanding these calculations is essential for accurately determining average speed in different contexts. Mastering these concepts enhances comprehension of motion analysis in physics.
aaquib
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Average Speed? How do I calculate??

How do I calculate average speed on a position time graph? Velocity time graph?


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Aaquib
 
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On a position vs time graph, the average velocity is found by dividing the total displacement by the total time. In other words, (position at final point - position at initial point) / (time at final point - time at initial point).

For a velocity vs time graph, you can simply do (Final velocity - initial velocity) / 2.
 
hunter151 said:
On a position vs time graph, the average velocity is found by dividing the total displacement by the total time. In other words, (position at final point - position at initial point) / (time at final point - time at initial point).

For a velocity vs time graph, you can simply do (Final velocity - initial velocity) / 2.
For the velocity time graph, how do I get the average speed for the entire set of data? It starts at the origin, then goes up to (120,25) for A, and then the final point is F which is (720, -140)
 
In that case you would have to find the total displacement of the object, and divide that by the time it traveled.

To find the displacement on a V(t) graph, you need to look at the area under the curve. In this case, you would get two triangles, one above and one below the t axis (assuming the lines connecting your points are straight). Subtract the area of the triangle under the t axis from the area of the triangle above the t axis, and divide this by total time traveled. You are subtracting area below from area above because the object is traveling with a negative velocity (backwards) in the region below the t axis.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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