The discussion revolves around a problem involving average speed calculations for a round trip, where the original equation is given as 240/s + 240/(s+11) = 8. Participants are exploring the implications of the solutions found for the variable s, which represents speed.
There is an ongoing exploration of the problem, with some participants questioning the correctness of the equation and the interpretation of the results. Guidance has been offered regarding the need to clarify the equation's structure and the implications of the speeds derived.
Participants note that the problem may not specify the next steps clearly, leading to confusion about how to proceed with the calculated speeds. There is also mention of a homework template that may not have been utilized correctly in the initial post.
Is the program asking for the two speeds for the round trip? If so, 55 and -6 are NOT the answers. -6 is not a reasonable answer unless the car somehow made the trip in reverse. In any case, car speedometers don't register negative speeds.Tyrion101 said:I've solved my equation, which was originally 240/s + 240/s+ 11 = 8 as, s = 55 and s = -6. It's asking for the average speed to and from a place.It asks me to use s and s+11 and s as my two speeds, but I've tried using 55 and -6 both, it solves all portions of the equation, but I'm lost as what to do next. The program doesn't say what to do next, it just says tell me the answer.
This means ##\frac{240}{s} + \frac{240}{s} + 11 = 8##240/s + 240/s+ 11 = 8