Multiplying numbers from One set with another set

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SUMMARY

The discussion centers on calculating the sum "S" from the products of two sets: Q (odd integers from 1 to 29) and R (even integers from 2 to 30). The correct answer for S, derived from multiplying the sum of the odd integers (225) by the sum of the even integers (240), is definitively 54,000. The method discussed highlights the efficiency of using summation formulas for rapid calculations, rather than manually computing each product.

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Homework Statement



Bob makes two sets: one with all the even integers between 1 and 30 inclusive, and another with all the odd integers inclusive. He called the sets Q and R. He multiplied each number from Q with each number in R. Then he added the 225 products together and called the result "S". What number does S represent?

(A) 8,000 (B) 18,000 (C) 36,000 (D) 54,000 (E) 86,000

Homework Equations

The Attempt at a Solution



Set Q = {1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29}
Set R = {2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30}

I noticed if I took 1 from Q and multiplied with every number in R, I get multiples of 2 from 2 to 30
Likewise, if I took 3 from Q and multiplied with every number in R, I get multiples of 6 from 6 to 90 and so on.

# from Q Range Sum (Added first term and last term and multiplied by 7 and then added the middle #)
1 2 to 30 32 * 7 + 16 = 240
3 6 to 90 96 * 7 + 48 = 720
5 10 to 150 160 * 7 + 80 = 1200
7 14 to 210 224 * 7 + 112 = 1680
9 18 to 270 288 * 7 + 144 = 2160

I stopped here because I noticed the sums were odd multiples of 240.

So then I found the first term which is 240 and the last term which would be 240 * 29 = 6960. The middle # here would be 3600.

6960 + 240 = 7200. There are 7 pairs of 7200 and the left out middle number 3600, thus the sum would be 54,000.

I was wondering if there is a shorter or easier or alternative method of solving this problem.
 
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Yes. Multiply the sum of the odds by the sum of the evens. 225x240 = 54000.
 
And there is a formula you can use for those sums to make it even faster.
 

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