# Homework Help: Average Velocity of a Car Whilst Braking

1. Sep 28, 2010

### BraedenP

I don't require an answer to the problem itself, but rather a method I can use to solve it:

1. The problem statement, all variables and given/known data

You spot a deer down the road, so you brake to stop before hitting the deer. If your initial speed was 23m/s, what was your average velocity during braking? Deceleration was constant throughout braking.

2. Relevant equations

v=d/t
a=v/t

3. The attempt at a solution

I can't even begin to solve it, because I'm pretty sure I require an additional piece of data, such as the stopping distance, or the magnitude of the deceleration. Is there a way to solve it without this data?

Any help would be greatly appreciated!

2. Sep 28, 2010

### phyzguy

You don't need any additional data. Try drawing a graph of the velocity vs time, given that the deceleration is constant. What does it look like? What then is the average velocity? Does it depend on the magnitude of the deceleration?

3. Sep 28, 2010

### BraedenP

I would do that, but I don't know how long it takes the car to decelerate to 0m/s, because I wasn't given a time, either. If I knew the time, I could solve the problem easily.

I can't graph velocity vs. time without a time to plot against.

4. Sep 28, 2010

### phyzguy

Then try picking a couple of different decelerations, say 23 m/s^2 (in which case it will take 1 second to come to a stop) and 230 m/s2 (in which case it will take 0.1 s to come to a stop). See what you get for the average velocity in these two cases.

5. Sep 28, 2010

### BraedenP

I get 7.5m/s for both of them. However, if I pick some arbitrary number like 540m/s, I get an average velocity of 9.5m/s. For some reason, I'm still not getting how they're related.

6. Sep 28, 2010

### phyzguy

You must not be calculating the average correctly. The point is that if a function changes linearly from an initial value of Fi to a final value of Ff, then the average is just (Fi-Ff)/2. In this case, the velocity changes linearly from 23 m/s to 0 m/s, so the average velocity is just 23/2 = 11.5 m/s, and it doesn't matter what the rate of deceleration is, as long as it is constant.

7. Sep 28, 2010

### BraedenP

Oh, okay. That makes sense! So basically, it's just like finding the average of any other two magnitudes; the acceleration has no impact on it since it's constant.

Thanks a bunch! I appreciate it.