- #1

Violagirl

- 114

- 0

## Homework Statement

A falling object moves so that its height x above the ground at time t is given by the following equation: x = 100 m - (4.9 s

^{-2})t

^{2}. Find its average velocity from t = 0 t t = 2 s.

## Homework Equations

Average velocity = Δx/Δt

## The Attempt at a Solution

I was able to work it out to the point where I solved for x by plugging in the times given for 0 secs and 2 secs.

For t = 0:

x = 100 m - (4.9 s

^{-2}* (0 s)

^{2}

= 100 m

For t = 2:

x = 100 m - (4.9 s

^{-2}* (2 s)

^{2}

= 19.6 m

Solving for t

^{2}in the equation, I get:

100 m/4.9 s

^{-2}= t

^{2}

Final answer of 4.52 m s

^{-2}

For the average velocity equation (and t), I realize this does not work all that great as m will be canceled in setting up the average velocity equation and am only left with seconds for time. I'm not sure what it is that I'm doing wrong in this problem. Thank you everyone for your help.