Average velocity when the interval has a domain

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Homework Help Overview

The problem involves finding the average velocity of a ball thrown into the air, described by the height function s(t) = 40t - 16t², over a time interval (t, 2) where 0 < t < 2. The focus is on understanding how to calculate average velocity when the initial time variable is not fixed.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the need to determine how to approach the calculation of average velocity given the variable t. Questions arise about whether to substitute specific values for t and how to handle the interval constraints.

Discussion Status

Participants are exploring the relationship between the average velocity and the variable t, noting that the average velocity will be a function of t. Some guidance has been provided on using the endpoints of the interval to express the change in position.

Contextual Notes

There is an emphasis on the fact that t is not fixed and is constrained within the interval (0, 2), which affects the calculation of average velocity. Participants are questioning how to proceed without a specific value for t.

Biscuit
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Homework Statement



If a ball is thrown into the air with a velocity of 40 ft/sec, its height (in feet) after t seconds is given by
s(t) = 40t -16t^2.

Find the average velocity, vAV (t), of the ball over the time interval (t, 2), for 0 < t < 2.

Homework Equations


change of x/change of t[/B]

The Attempt at a Solution


Other questions were a breeze but this one stumped me. Am I just supposed to plug in 1 for t variable here? I feel like that doesn't make sense because the question before this was on the interval (1,2). I also thought maybe I should just replace the variable with the domain it has given me and write down a super long unsolved equation. Any help is appreciated thanks![/B]
 
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I would let:

##\Delta t=2-t##

Now, the average velocity is the total displacement divided by the time elapsed:

##\overline{v}=\dfrac{\Delta s}{\Delta t}=?##
 
MarkFL said:
I would let:

##\Delta t=2-t##

Now, the average velocity is the total displacement divided by the time elapsed:

##\overline{v}=\dfrac{\Delta s}{\Delta t}=?##
but what value would go in for t here?
 
Biscuit said:
but what value would go in for t here?

##t## is not set to any specific value, all we know is ##0<t<2##, so your average velocity will depend on ##t##, that is, it will be a function of ##t##.
 
MarkFL said:
##t## is not set to any specific value, all we know is ##0<t<2##, so your average velocity will depend on ##t##, that is, it will be a function of ##t##.
So there will be no exact answer in the end won't there be a t variable?
 
Biscuit said:
So there will be no exact answer in the end won't there be a t variable?

Yes, the average velocity will depend on ##t##. It will give you a formula into which you can plug any allowed value of ##t## to find the average velocity corresponding to that value of ##t##.
 
MarkFL said:
Yes, the average velocity will depend on ##t##. It will give you a formula into which you can plug any allowed value of ##t## to find the average velocity corresponding to that value of ##t##.
how would I find what the change of position is if I have no first value of t to plug in?
 
Biscuit said:
how would I find what the change of position is if I have no first value of t to plug in?

You would use 2 as your final time and ##t## as your initial time, i.e.:

##\Delta s=s(2)-s(t)=?##
 

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