Two long horizontal straight parallel wires are 28.28 cm apart and each carries a current of 2.2 A in the same direction, namely, due south. What is the B-field at a point that is a perpendicular distance of 23 cm from both wires? Answer in microtesla. B= (u0*I)/(2Pi*r) u0= 4Pi*10^-7= 1.26*10^-6 23cm= 0.23m 2.2A*2= 4.4A B= (1.26*10^-6)(4.4)/(2Pi*0.23)= 3.84*10^-6T= 3.84uT 3.84uT is incorrect. I don't really know what to do here. I'm pretty sure I have the right equation, but the fact that it's two wires throws me off. Do I add the currents or subtract them? Does the 28.28cm come into play? Is my conversion from tesla to microtesla correct? Where am I going wrong? Any help would be greatly appreciated.