Balancing Charges & Electrons in Cr3++CIO3-+H2O → Cr2O72-+Cl-+H+

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SUMMARY

The discussion focuses on balancing the redox reaction Cr3+ + ClO3- + H2O → Cr2O72- + Cl- + H+. Participants emphasize the importance of assigning oxidation numbers correctly to balance charges and electrons. The oxidation states of chromium and chlorine are critical, with Cr3+ having a +3 charge and ClO3- contributing to the overall charge balance. The final balanced equation requires careful tracking of electron transfer and charge conservation.

PREREQUISITES
  • Understanding of oxidation states in redox reactions
  • Familiarity with balancing chemical equations
  • Knowledge of the concepts of oxidation and reduction
  • Basic chemistry terminology related to ions and charges
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  • Study the principles of balancing redox reactions using half-reaction methods
  • Learn about oxidation states and their significance in chemical reactions
  • Explore examples of balancing complex redox equations
  • Review the role of water in redox reactions and its impact on charge balance
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Homework Statement


Hi. :) I'm supposed to balance the formula and write the values.

Cr3++CIO3-+H2O → Cr2O72-+Cl-+H+

Specify:Amount of electrons
and: Charges

The Attempt at a Solution


I don't really got any clue. Please help!
Cr3+ have +3
The oxygen have -2 and then?
Cr3++CIO3-+H2O → Cr2O72-+Cl-+H+ ?
 
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