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Preparation and naming of coordination compounds

  • Thread starter Rujano
  • Start date
  • #1
17
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Homework Statement



Hi.
The combination of Fe(II), H2O, Cl- y NH4+ yields 3 coordination compounds, one of which is:

[Fe(H2O)6]Cl2

Which are the other ones?

Homework Equations





The Attempt at a Solution



Even though I sort of know how the compounds could be formed I don't why or rather , how can I tell that only 3 will be formed....

For instance, I think that some of the compounds could be:

(NH4)3[Fe(H2O)Cl5]

[Fe(H2O)3Cl3]Cl

(NH4)2[Fe(H2O)2Cl4]

How can I tell if they are correct? and how can I know that they should be three for example (in this case I already have four :S)
 
Last edited:

Answers and Replies

  • #2
AGNuke
Gold Member
455
9
If you are talking about the co-ordination Number 6, then the following possibilities are there with Co-ordination Sphere:

1. Have +2 charge; [Fe(H2O)6]Cl2
2. Have +1 charge; [Fe(H2O)5Cl]Cl
3. Have 0 charge; [Fe(H2O)4Cl2]
4. Have -1 charge; NH4[Fe(H2O)3Cl3]
5. Have -2 charge; (NH4)2[Fe(H2O)2Cl4]
6. Have -3 charge; (NH4)3[Fe(H2O)Cl5]
7. Have -4 charge. (NH4)4[FeCl6]

See, I formed 6 or 7 compounds, So what could you be asking that the compulsory presence of mentioned species, either inside or outside the sphere. Then there can be 3.

Also, there's no way to tell what will happen until you write down all possible cases.
 

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