Chemistry Balancing Equations: 2H2 + O2 -> 2H2O - 180g of Water Produced

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The discussion revolves around calculating the amount of water produced from the reaction of dihydrogen and dioxygen. The balanced equation is 2H2 + O2 = 2H2O, indicating that 2 moles of H2 yield 2 moles of H2O. The participant calculates that 20 g of H2 would produce 180 g of water, but questions the feasibility since the total mass of reactants is only 40 g. It is suggested to determine the limiting reagent to accurately assess the maximum water yield. The conversation highlights the importance of stoichiometry and mass conservation in chemical reactions.
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Homework Statement


if 20.0 g of dihydrogen is reacted with 20.0 g of dioxygen , how many grams of water is produced?


Homework Equations





The Attempt at a Solution


balancing
2H2 + O2 = 2H20
now 2 mole h2 gives 2mole H2O
so 20/2 moles of H2 will give 10 moles H2O
10 x 18 = 180 g
...
am i right?
 
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You start with 20g + 20g = 40g of reactants, is it possible to produce 180g of water?
 
Borek said:
You start with 20g + 20g = 40g of reactants, is it possible to produce 180g of water?

the nhow do i do it?
 
What if you start calculations with oxygen?
 
Start by finding out the limiting reagent. :)
 
Sigh. I did my best to not use this term as a hint.
 
Borek said:
Sigh. I did my best to not use this term as a hint.

Sorry Borek. :)
 

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