1. The problem statement, all variables and given/known data A horizontal uniform bar of mass 260 kg and length L = 3.0 m is placed on two supports, labeled A and B, located as shown in the diagram. A block of mass 60 kg is placed on the right end of the bar. Find the normal forces FA and FB exerted on the bar by the supports. Enter your answer in Newtons (N). Use g = 9.8 m/s2. 2. Relevant equations ##\Sigma F = m*a## ## \tau = F * D ## 3. The attempt at a solution I had thought to use a system of equations to solve the problem, however I simply cannot find/get to work a second equation. I believe I have one correct equation: ## F_A + F_B = (260 + 60) * 9.8 ##. This being from Newton's Second Law. I tried to work out another equation with the torques of A and B being equal to zero (based on an equilibrium assumption), using the position of the red square as the starting point I tried: ## -.5*F_A + 1.5*F_B = 0 ##. This however proved fruitless. At this point I am out of ideas. As always, my thanks in advance for any assistance.