Ball Drop Question: How High Will It Go?

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Homework Help Overview

The problem involves a ball of mass 0.35 kilograms that is 1.1 meters above the ground with an initial speed of 1.3 meters per second directed upwards. The question seeks to determine the maximum height the ball will reach, assuming no energy loss due to air friction.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss using energy conservation equations, specifically potential and kinetic energy, to find the maximum height. There is also mention of using kinematic equations as an alternative approach. Some participants express confusion over calculations and results.

Discussion Status

The discussion includes various attempts to solve the problem using different methods. Some participants have shared their calculated results, while others question the accuracy of their approaches. There is no explicit consensus on the best method, but multiple interpretations and methods are being explored.

Contextual Notes

Participants note potential issues with calculations, including possible typos or algebraic errors. The original poster expresses uncertainty about the correctness of their approach, indicating a need for clarification on the equations used.

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Homework Statement


A ball of mass 0.35 kilograms is currently 1.1 meters off the floor and has a speed of 1.3 meters per second straight up. Assuming no energy is converted by air friction, how high will the ball go?


Homework Equations


PE=mgh
KE=1/2mv^2


The Attempt at a Solution


Since there is no friction or work, i set the equation as mgh=mgx+1/2mv^2, solving for x(final height) but I get the wrong answer. And I'm pretty sure this is the right equation to use.
 
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yes I think that's a way to do it, maybe typo on calculator. I got 1.186m
 
ice ace said:
yes I think that's a way to do it, maybe typo on calculator. I got 1.186m

1.186? How did u get that? These are the values I plugged in.
(.35*1.1*9.81)=(9.81*.35*x)+(.5*.35*1.3^2)
From this x=(((.35*1.1*9.81)-(.(5*.35*1.3^2))/(9.81*.35)
Using a Ti-83, and not rounding any answers, I get 1.014.

Im confused...
 
i think easier way is to use kinematics equation : vf^2=vi^2+2ad then add 1.1m with d to get it
 
ice ace said:
i think easier way is to use kinematics equation : vf^2=vi^2+2ad then add 1.1m with d to get it

Yup that did it. Thanks! Though I'm still wondering why my equations didn't work. O well, thanks for help
 
OMG nvm I'm a idiot. I can't do basic algebra -_____-, mine equation does work
 

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