Ball hitting block, elastic collision

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SUMMARY

A 0.500 kg ball attached to a 70 cm cord strikes a stationary 2.5 kg block in a perfectly elastic collision. The initial potential energy of the ball is calculated to be 3.43 J, leading to a kinetic energy of 2.62 J just before impact. Using conservation of momentum and energy equations, the final velocities are determined to be -1.75 m/s for the ball and 0.87 m/s for the block after the collision. The discussion highlights the importance of understanding elastic collision principles and energy conservation in physics.

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Homework Statement



.500kg ball attached to a cord that is 70 cm long. ball strikes a 2.5kg block at rest

what is the speed of the ball just before hitting the block
and collison is perfectly elastic find speed of ball and block after collision

Homework Equations





The Attempt at a Solution


Uo=MGY
(.5)(9.8)(.7)= 3.43J
Ko=0
Uf=0
J=.5(.5)v^2= 2.62

part b
2.62=V2f-V1f
1.31=.5V1f+2.5V2f

matrix on calc
V1f= -1.75
V2f=.87
 
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I don't understand the question. Do you have a diagram? How is the cord attached? Is it a spring or something?
 

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