- #1

Neon32

- 68

- 1

## Homework Statement

Two blocks are free to slide along a frictionless wooden track ABC as shown below. The block of mass m1 = 5.09 kg is released from A. Protruding from its front end is the north pole of a strong magnet, repelling the north pole of an identical magnet embedded in the back end of the block of mass m2 = 9.50 kg, initially at rest. The two blocks never touch. Calculate the maximum height to which m1 rises after the elastic collision.

Answer in m

figure:

## Homework Equations

We'll use law of energy conservation: KEi+P.Ei=K.Ef+P.E

+

Vf=(m1-m2/m1+m2)Vi

## The Attempt at a Solution

K.Ei+P.Ei=K.Ef+P.Ef

m1gh=1/2 m1 V1i

^{2}[/B]

So we get V1i=9.90 m/s.

Substituting in V1f=(m1-m2/m1+m2)Vi, w get:

V1f=-3.3m/s

1)I want to know if what I did above is correct.

2) My second question is

I'll use the law of energy conservation again so we can find the maximum height:

The second body will acquire velocity so there is kinetic energy after collision:

1/2m1 v1

^{2}+1/2 m2 V2

^{2}=m1gh(new height)

Is this one correct?

Last edited: