1. The problem statement, all variables and given/known data Two blocks are free to slide along a frictionless wooden track ABC as shown below. The block of mass m1 = 5.09 kg is released from A. Protruding from its front end is the north pole of a strong magnet, repelling the north pole of an identical magnet embedded in the back end of the block of mass m2 = 9.50 kg, initially at rest. The two blocks never touch. Calculate the maximum height to which m1 rises after the elastic collision. Answer in m figure: 2. Relevant equations We'll use law of energy conservation: KEi+P.Ei=K.Ef+P.E + Vf=(m1-m2/m1+m2)Vi 3. The attempt at a solution K.Ei+P.Ei=K.Ef+P.Ef m1gh=1/2 m1 V1i2 So we get V1i=9.90 m/s. Substituting in V1f=(m1-m2/m1+m2)Vi, w get: V1f=-3.3m/s 1)I want to know if what I did above is correct. 2) My second question is I'll use the law of energy conservation again so we can find the maximum height: The second body will acquire velocity so there is kinetic energy after collision: 1/2m1 v12+1/2 m2 V22=m1gh(new height) Is this one correct?