I don't get it!! problem: A ball is launched up a semicircular chute in such a way that at the top of the chute, just before it goes into free fall, the ball has a centripetal acceleration of magnitude 2g. And the distance between the bottom and the top of the chute is 2R. How far from the bottom of the chute does the ball land? I realize it is just another projectile motion prob. I calculated the velocity to be (2gR)^(1/2) using the formula (m=v2/radius) for circular motion. and the time was derived using kinematic equation (t=(2R/g)^(1/2)). I DON'T KNOW WHAT I AM DOING WRONG. Sorry, but I'm so frustrated. Is there anyone out there who can solve this?????