- #1

Wanting to Learn

## Homework Statement

:[/B]A ball player catches a ball 3.33 s after throwing it vertically upward.

With what speed did he throw it?

What height did it reach?

## Homework Equations

:[/B]d = v

_{0}t + .5at

^{2}

I'm not sure whether this is one of the equations which should be used for this problem.

[I also have from class (just started AP Physics 1) a list of 5 other equations which I could try to post if that would be helpful, I'm not sure what most of them mean/how any of them could be applied (aside from d=tv).]

gravity 9.8 m/s

^{2}(pulling the ball downwards, not sure how to use this info in solving)

3.33s/2=1.665s ball spends going in each direction (up and down)

## The Attempt at a Solution

:[/B]I'm not really sure how to start/what to do with this problem.

I think there need to be 2 parts, going up and going down.

d = 0 + .5*-9.8*1.665 = -8.1585

__m__• s = m/s

s

^{2}

I'm not sure what this number represents, if it does represent anything. I make acceleration negative because of the gravity pulling down but I'm guessing that is not how it needs to be used. Also I think this ignores the acceleration of the ball being thrown up, which was not given, so I'm very confused about what I should do.

Thank you in advance for any and all help.