Ball Trajectory: Solve for x(t) & y(t) & y(x)

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SUMMARY

The discussion focuses on solving the trajectory of a cannonball shot at an angle θ, specifically finding the position functions x(t) and y(t) over time, and subsequently deriving the trajectory equation y(x). The equations derived are x(t) = Vocos(θ)t and y(t) = Vosin(θ)t - 0.5gt². To find y as a function of x, participants suggest isolating time t from the x(t) equation and substituting it into the y(t) equation, which is a standard method in projectile motion analysis.

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Homework Statement



A cannon shoots a ball at an angle \theta above the horizontal ground

a) Neglecting air resistance, find the ball's position (x(t) and y(t)) as a function of time.

b) Take the above answer and find an equation for the ball's trajectory y(x).

Homework Equations



\frac{dx}{dt} = Vocos(\theta)

\frac{dy}{dt} = Vosin(\theta) - gt

The Attempt at a Solution



Okay, so I integrated both sides of both equations and ended up with:

x(t) = Vocos(\theta)t

y(t) = Vosin(\theta)t - 0.5gt2

which I'm pretty sure solves part a), but I'm having a lot of trouble finding a function of y in terms of x for part b). I tried messing around with some trigonometric identities but I get nowhere. Any tips?
 
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Try to find t in terms of x or y from one of the equations you found for part a. Substitute that in the other equation.
 

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