Calculating Trajectory Equation of Motion for a Rock Touching a Wall

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The discussion revolves around deriving the trajectory equation of motion for a rock touching a wall, using equations that relate horizontal and vertical motion. Participants explore various equations to express the trajectory, including attempts to eliminate variables such as velocity and angle. There is a focus on simplifying the problem by analyzing the middle section of the trajectory and using geometric relationships to derive necessary equations. Ultimately, the conversation emphasizes the importance of choosing an appropriate origin for the trajectory to simplify calculations. The group concludes that multiple methods can yield valid results, depending on the chosen parameters and equations.
  • #31
PeroK said:
It was even simpler to have the origin on the parabola itself at the top of the first wall, so that ##c = 0##
Yes that is a better choice.
 
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  • #32
compaq65 said:
Why there is a ##c## constant, if in
$$y = x\tan \theta - \frac{gx^2}{2v^2}\sec^2 \theta$$
I can only notice ##a## and ##b## coefficients. Because of that I get a little bit different answers. Which method is correct?
You should realize by now that this problem has nothing to do with the kinematics of the projectile. Velocity and acceleration are irrelevant. Your answer does not depend on them. The same question can be asked about a parabola painted on a wall.
 
  • #33
Everything is clear now. Thanks, you all helped me a lot!
 
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