Calculating Trajectory Equation of Motion for a Rock Touching a Wall

  • Thread starter Thread starter compaq65
  • Start date Start date
  • Tags Tags
    Rock Wall
Click For Summary

Homework Help Overview

The discussion revolves around calculating the trajectory equation of motion for a rock that touches a wall, focusing on the relationships between various parameters such as height, distance, angle, and velocity. The subject area includes projectile motion and kinematics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants explore different equations of motion and relationships between variables, such as height (h), distance (x), angle (α), and velocity (v). There are attempts to derive equations from the trajectory and to express certain variables in terms of others. Questions arise about the adequacy of the equations and the assumptions made, particularly regarding the use of tangent and the relationships between the parameters.

Discussion Status

The discussion is active, with participants sharing equations and suggesting different approaches to analyze the problem. Some participants propose using geometric insights and symmetry, while others focus on algebraic manipulation. There is recognition of the need for additional equations to resolve the system of variables, and various interpretations of the trajectory are being explored.

Contextual Notes

Participants note that they are working with multiple unknowns and equations, leading to challenges in finding a solution. There is also mention of constraints related to the problem setup, such as the horizontal distance being fixed at 3r and the need to eliminate certain variables from the equations.

  • #31
PeroK said:
It was even simpler to have the origin on the parabola itself at the top of the first wall, so that ##c = 0##
Yes that is a better choice.
 
Physics news on Phys.org
  • #32
compaq65 said:
Why there is a ##c## constant, if in
$$y = x\tan \theta - \frac{gx^2}{2v^2}\sec^2 \theta$$
I can only notice ##a## and ##b## coefficients. Because of that I get a little bit different answers. Which method is correct?
You should realize by now that this problem has nothing to do with the kinematics of the projectile. Velocity and acceleration are irrelevant. Your answer does not depend on them. The same question can be asked about a parabola painted on a wall.
 
  • Like
Likes   Reactions: pbuk
  • #33
Everything is clear now. Thanks, you all helped me a lot!
 
  • Like
Likes   Reactions: berkeman and PeroK

Similar threads

  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 97 ·
4
Replies
97
Views
6K
  • · Replies 9 ·
Replies
9
Views
1K
  • · Replies 3 ·
Replies
3
Views
1K
Replies
46
Views
6K
Replies
1
Views
1K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 4 ·
Replies
4
Views
1K
Replies
2
Views
2K