Balls dropped and thrown at the same time

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The discussion focuses on a physics problem involving two balls: one thrown upwards from a building and the other dropped from the same height. The building's height is 19.3 meters, and the initial speed of the first ball must be calculated to ensure both balls hit the ground simultaneously. The relevant equations used include \(y = v_0 t - \frac{1}{2} g t^2\) and \(y = \frac{1}{2} (v_0 - v) t\). The initial speed for the first ball was incorrectly calculated as -22.5 m/s, and the height for a given initial speed of 8.80 m/s was incorrectly calculated as -3.66 m.

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A ball is thrown straight up from the edge of the roof of a building. A second ball is dropped from the roof a time of 1.14 later. You may ignore air resistance.A- If the height of the building is 19.3 , what must the initial speed be of the first ball if both are to hit the ground at the same time?B- Consider the same situation, but now let the initial speed of the first ball be given and treat the height of the building as an unknown. What must the height of the building be for both balls to reach the ground at the same time for v0 = 8.80 .

i need a help for this question please.. 3 hours and I am getting a wrong answers..

i used these formulas : y=v0.t-1/2.g.t2 , and this : y=1/2.(v0-v).t
 
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It would help if you showed what you have done. Yes, y= v_0t- (1/2)gt^2 will help here. The second ball is dropped- i.e. has v_0= 0. So when will that ball hit the ground? Set t equal to that for the first ball and solve for v_0.
 


for A .. i got this answer : -22.5
right?
 
Last edited:


for B.. i got the answer -3.66

and both the answers are wrong.. !
 


HallsofIvy said:
It would help if you showed what you have done. Yes, y= v_0t- (1/2)gt^2 will help here. The second ball is dropped- i.e. has v_0= 0. So when will that ball hit the ground? Set t equal to that for the first ball and solve for v_0.

I need a help and check for my answers.. and i showed you the formula and you said that this formula is right.. but the answers are wrong..
 

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