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Balmer, Lyman, and Paschen series

  1. Feb 14, 2010 #1
    1. The problem statement, all variables and given/known data

    4. (a) Find the shortest wavelength photon emitted by a downward electron transition in the
    Lyman, Balmer, and Paschen series of the hydrogen atom.

    My only question is, what energy state is the electron starting from? is it n=infinity? or is there some part of this im missing?
  2. jcsd
  3. Feb 14, 2010 #2


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    Electrons can start from any energy level and end up in any energy level. Which transition would give the greatest frequency?
  4. Feb 14, 2010 #3
    well the higher the starting energy level, the shorter the wavelength, so i would assume n=infinity,

    so whats n=infinity for hydrogen?
  5. Feb 15, 2010 #4


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    It means a free electron in rest, very far away from the nucleus, so no force acting on it.

  6. Feb 20, 2010 #5
    I have the same problem, I need to find "E-max" for hydrogen. I know that I should take ((2.18*10^-18)/(6.63*10^-34)) * ((1/n)-(1/m)) (Where n>m)
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