Balmer, Lyman, and Paschen series

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Homework Help Overview

The discussion revolves around identifying the shortest wavelength photon emitted during electron transitions in the Lyman, Balmer, and Paschen series of the hydrogen atom. Participants are exploring the initial energy state of the electron and its implications for the transitions being considered.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants are questioning the starting energy state of the electron, particularly whether it begins at n=infinity. There is also discussion about how the starting energy level affects the wavelength of emitted photons, with some suggesting that higher starting levels yield shorter wavelengths.

Discussion Status

The discussion is active, with participants raising questions about the initial conditions for the electron transitions and exploring the relationship between energy levels and photon wavelengths. Some guidance has been offered regarding the implications of starting from n=infinity, but no consensus has been reached.

Contextual Notes

Participants are grappling with the definitions and implications of energy states in the context of hydrogen transitions, and there is mention of a formula related to energy calculations that may require clarification.

warfreak131
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Homework Statement



4. (a) Find the shortest wavelength photon emitted by a downward electron transition in the
Lyman, Balmer, and Paschen series of the hydrogen atom.

My only question is, what energy state is the electron starting from? is it n=infinity? or is there some part of this I am missing?
 
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Electrons can start from any energy level and end up in any energy level. Which transition would give the greatest frequency?
 
well the higher the starting energy level, the shorter the wavelength, so i would assume n=infinity,

so what's n=infinity for hydrogen?
 
It means a free electron in rest, very far away from the nucleus, so no force acting on it.

ehild
 
I have the same problem, I need to find "E-max" for hydrogen. I know that I should take ((2.18*10^-18)/(6.63*10^-34)) * ((1/n)-(1/m)) (Where n>m)
 

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