Bohr Model (Lyman,Balmer,Paschen series)

[Nope]

Homework Statement

Determine the wavelengths of photons given off for the 3^rd line in the Lyman series , the 2^nd line in the Balmer series, and the 1^st line in the Paschen series.

The question is weird,
I don't understand what the "line" mean...

"1^st line in the Paschen series " Is it mean n_i is 1? Paschen series:n_f=3
Thanks

Homework Equations

The Attempt at a Solution

 

[ojs]

The 'line' is a spectral line (see http://en.wikipedia.org/wiki/Hydrogen_spectral_series), for the Lyman series it is the transitions from n >= 2 to the n = 1 state, for Balmer series its from n >= 3 to the n = 2 state and the Paschen series are transitions from n >= 4 to n = 3 state. The first line in each series is the transition from the next lowest number in the series to the lowest (so in the Lyman series the first line would be from n=2 to n=1) and the second line would be from from the third lowest to the lowest (in Lyman it would be n=3 to n=1) etc etc.
To calculate the wavelength you can use the Rydberg formula.

 

[Nope]

The 'line' is a spectral line (see http://en.wikipedia.org/wiki/Hydrogen_spectral_series), for the Lyman series it is the transitions from n >= 2 to the n = 1 state, for Balmer series its from n >= 3 to the n = 2 state and the Paschen series are transitions from n >= 4 to n = 3 state. The first line in each series is the transition from the next lowest number in the series to the lowest (so in the Lyman series the first line would be from n=2 to n=1) and the second line would be from from the third lowest to the lowest (in Lyman it would be n=3 to n=1) etc etc.
To calculate the wavelength you can use the Rydberg formula.

I see,
3^rd line in the Lyman series --> n_i=4
2^nd line in the Balmer series --> n_i=4
1^st line in the Paschen series ---> n_i=4
am i right?

 

[ojs]

I see,
3^rd line in the Lyman series --> n_i=4
2^nd line in the Balmer series --> n_i=4
1^st line in the Paschen series ---> n_i=4
am i right?

Yes, you are quite right here.