Banking curve problem (find maximum speed)

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
4 replies · 3K views
5ymmetrica1
Messages
88
Reaction score
0

Homework Statement


A car travels around a circular curve on a flat, horizontal road at a radius of 42meters.
the maximum frictional force between the tyres and the road is equal to 20% of the weight of the car
calculate the maximum speed at which the car can travel around the curve at a constant radius of 42 meters


Homework Equations


I think I am supposed to use v = √rg
But I don't have a set of answers for these problems so I am not sure as this doesn't include the part of the question, the maximum frictional force between the tyres and the road is equal to 20% of the weight of the car


The Attempt at a Solution



v = √42*9.8
∴ v = 20.29 m/s
 
Physics news on Phys.org
5ymmetrica1 said:

Homework Statement


A car travels around a circular curve on a flat, horizontal road at a radius of 42meters.
the maximum frictional force between the tyres and the road is equal to 20% of the weight of the car
calculate the maximum speed at which the car can travel around the curve at a constant radius of 42 meters


Homework Equations


I think I am supposed to use v = √rg
But I don't have a set of answers for these problems so I am not sure as this doesn't include the part of the question, the maximum frictional force between the tyres and the road is equal to 20% of the weight of the car


The Attempt at a Solution



v = √42*9.8
∴ v = 20.29 m/s

The centripetal force is mv^2/R but what force is in play to produce that force ? It's not mg since that's the weight of the entire vehicle. What's the static friction force?
 
I haven't studied any formula for static friction at this time in my physics course so I'm not quite sure what you mean sorry.

I know Fw = Fg (and Fv is equal but opposite in direction)

and that when split into vector components Fh = Fc

so is the frictional force Ff = FN (Normal force)?
 
5ymmetrica1 said:
I haven't studied any formula for static friction at this time in my physics course so I'm not quite sure what you mean sorry.

I know Fw = Fg (and Fv is equal but opposite in direction)

and that when split into vector components Fh = Fc

so is the frictional force Ff = FN (Normal force)?

You don't need the actual formula of friction since you know Fμ=0.2*G
 
5ymmetrica1 said:
I haven't studied any formula for static friction at this time in my physics course so I'm not quite sure what you mean sorry.

I know Fw = Fg (and Fv is equal but opposite in direction)

and that when split into vector components Fh = Fc

so is the frictional force Ff = FN (Normal force)?


If yo have a weight W sitting on the table and the coefficient of static friction is μ, how much horizontal force can you apply before it starts to slip?