Bankteller Problem: How Many Ways Can Both Men and Women Be Served?

  • Context: Undergrad 
  • Thread starter Thread starter rickdundee
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Discussion Overview

The discussion revolves around the "Bankteller Problem," which involves combinatorial mathematics related to selecting individuals from a group based on gender constraints. Participants are addressing two main questions: how many ways a specific number of men and women can be served, and the probability of such selections occurring randomly. The scope includes homework-related problem-solving and mathematical reasoning.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant proposes a solution for selecting 4 people, requiring 2 men and 2 women, calculated as (6 choose 2) * (4 choose 2) = 90.
  • Another participant suggests the probability of selecting 2 men and 2 women from a total of 10 people as 6C2 x 4C2 / 10C4 = 3/7.
  • A different participant presents a variation of the problem, asking how to select 5 people including 3 men and 2 women, and proposes a solution of (10c5)*(6c3)*(4c2).
  • One participant comments on the nature of the questions, suggesting they are likely homework-related.
  • Another participant provides a probability calculation for selecting 3 men and 2 women as 6C3 x 4C2 / 10C5 = 10/21.

Areas of Agreement / Disagreement

Participants present differing approaches and solutions to the problems posed, indicating that there is no consensus on the correctness of the proposed solutions or methods. The discussion remains unresolved regarding the accuracy of the calculations and the interpretations of the problems.

Contextual Notes

Some participants' solutions depend on the interpretation of the problem statements and the assumptions made regarding the selection process. There may be missing details or conditions that affect the calculations.

rickdundee
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HELP! Bankteller Problem

1. Homework Statement
There are 6 males and 4 females awaiting to see a teller at a bank.

Only 4 people can be served at one time.
1) How many ways can four of the people be picked and served one at a time, if they must include two(2) men and two(2) women?


2) If indeed the four people are picked randomly, what is the probability that the four will include two (2) men and two (2) women?
This is the question I am confused about.


3. The Attempt at a Solution
My solution for Problem#1: (6 choose 2) * (4 choose 2) = 90
 
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2) 6C2 x 4C2 /10C4 = 3/7
 
Last edited:
HELP! Bankteller Problem

Thank you. Could you check this.

It is the end of the day and there are 5 tellers, but each teller can only serve one person. Therefore only five people can be served, each by a teller, so the five people are picked at once.

1) How many ways can five of the people picked and served, if they must include 3 men and 2 women?

My solution: (10c5)*(6c3)*(4c2)

2) If indeed the 5 people are picked randomly, what is the probability that the five will include 3 men and 2 women?

My solution: If the solution to the first question is correct I should be able to figure it out.
 
This is bound to be homework.
 
Actually review of an even answer in the text.
 
2) Just as before,
6C3 x 4C2 / 10C5 =10/21
 

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