Jarvis323
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I think maybe you want the 1's place the be the ##\frac{\pi}{10}##'s place?
The discussion centers on the concept of expressing integers in base π, denoted as Zπ, and its implications for group structure. Participants debate whether Zπ can be considered a group under addition, given that operations yield results that do not align with traditional integer arithmetic. Key points include the representation of integers like 11 in this system and the assertion that 5 + 5 equals π in Zπ, which raises questions about the validity of the group's closure under addition. Ultimately, the consensus suggests that Zπ does not form a valid group due to inconsistencies in its operations.
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If that's true then the 100s place should be ##10\pi##, not ##\pi^2##. But then the set is just the integers scaled by ##\pi/10## which again is not interesting.Jarvis323 said:I think maybe you want the 1's place the be the ##\frac{\pi}{10}##'s place?
@Atran, I don't believe you understand how numbers can be represented in different bases.Atran said:A proper number is expressed in \pi in a similar way as a decimal integer is expressed in base 2. For example, 4375_{\pi} = 4{\pi^3}+3{\pi^2}+7{\pi}+5.
This makes no sense whatsoever. In any usual number base, such as base-2, base-3, base-8, base-10, base-16, base-64, the digits used run from 0 up to, but not including, the base. In your list, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, ##\pi##, your "base" lies between 3 and 4.Atran said:The only exception I make is that the 10 digits are included when expressing a number with \pi. To clarify, the first positive such numbers are: 0,1,2,3,4,5,6,7,8,9,{\pi},{\pi}+1,{\pi}+2,...,2{\pi},2{\pi}+1,...5{\pi},5{\pi}+1,5{\pi}+2,...,9{\pi}+8,9{\pi}+9,{\pi}^2,....