Base Pi Integers: Isomorphism with Rationals?

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SUMMARY

The discussion centers on the concept of expressing integers in base π, denoted as Zπ, and its implications for group structure. Participants debate whether Zπ can be considered a group under addition, given that operations yield results that do not align with traditional integer arithmetic. Key points include the representation of integers like 11 in this system and the assertion that 5 + 5 equals π in Zπ, which raises questions about the validity of the group's closure under addition. Ultimately, the consensus suggests that Zπ does not form a valid group due to inconsistencies in its operations.

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  • #31
I think maybe you want the 1's place the be the ##\frac{\pi}{10}##'s place?
 
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  • #32
Jarvis323 said:
I think maybe you want the 1's place the be the ##\frac{\pi}{10}##'s place?
If that's true then the 100s place should be ##10\pi##, not ##\pi^2##. But then the set is just the integers scaled by ##\pi/10## which again is not interesting.
 
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  • #33
The OP seems to have bailed from this thread. It's probably not useful to try and figure out what he really meant. (Is π = 10?)
 
  • #34
Atran said:
A proper number is expressed in \pi in a similar way as a decimal integer is expressed in base 2. For example, 4375_{\pi} = 4{\pi^3}+3{\pi^2}+7{\pi}+5.
@Atran, I don't believe you understand how numbers can be represented in different bases.
In base 2, the digits are 0 and 1. Counting would proceed from 0, 1, 10, 11, 100, 101, 110, and so on, with all numbers in this list being in binary, and corresponding to the decimal number 0, 1, 2, 3, 4, 5, 6, and so on.
In base 3, the digits are 0, 1, and 2. Any integer could be represented as a sum of multiples (0, 1, or 2) powers of 3. For example, the decimal number 34 (= 27 + 6 + 1) would be written in base-3 (ternary or trinary) as 121 (## 1 \cdot 3^3 + 2 \cdot 3^1 + 1 \cdot 3^0##).
Conversion to any other positive integer base of 2 or larger would be similar.
Atran said:
The only exception I make is that the 10 digits are included when expressing a number with \pi. To clarify, the first positive such numbers are: 0,1,2,3,4,5,6,7,8,9,{\pi},{\pi}+1,{\pi}+2,...,2{\pi},2{\pi}+1,...5{\pi},5{\pi}+1,5{\pi}+2,...,9{\pi}+8,9{\pi}+9,{\pi}^2,....
This makes no sense whatsoever. In any usual number base, such as base-2, base-3, base-8, base-10, base-16, base-64, the digits used run from 0 up to, but not including, the base. In your list, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, ##\pi##, your "base" lies between 3 and 4.
A major flaw in your list is that for ##10_\pi##, or ##1 \cdot \pi^1 + 0 \cdot \pi^0##, you list this as being larger than 9. In fact, as already mentioned, it lies between 3 and 4.

Thread closed.
 

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