Basic Algebra Problem: Solving a/b/c=?

[Ray Vickson]

Interesting, an example of right-to-left parsing for a/b/c. So, in the new Maple worksheet, it gives a/b/c = a/(b/(c)) = a/(b/c) ? I'll try to remember that, if I ever need to use Maple.

edit: well, I guess I don't need to remember anything, since it draws the solidus on-screen as you're typing.

Right, but it does need a right arrow to get get out of the fraction, or to get out of an exponent x^n or a subscript x_n.

 

[Ray Vickson]

Interesting, an example of right-to-left parsing for a/b/c. So, in the new Maple worksheet, it gives a/b/c = a/(b/(c)) = a/(b/c) ? I'll try to remember that, if I ever need to use Maple.

edit: well, I guess I don't need to remember anything, since it draws the solidus on-screen as you're typing.

Right, but it does need a keyboard right arrow to get get out of the fraction, or to get out of an exponent x^n or a subscript x_n. However, to compensate, one can enter many types of fractions without using brackets (parentheses?), such as a/(b + c*e + f), which is entered as a/b+c*e+f→, etc, and displays on screen exactly as you finally want it exactly when you type it.

 

[adjacent]

Everyone!I have got a nice solution to this fraction thing.
Let's simplify a/b/c/d/e/f/g/h/i/j/k ...z
First take the $\frac{a}{b}$ and divide c by it.
That gives $\frac{a}{b}*\frac{1}{c}$ by taking the reciprocal.
So it's very simple.
$\frac{a}{b}*\frac{1}{c}*\frac{1}{d} ...\frac{1}{z}$
Which is same as:
$\frac{a}{bcdefghijklmnopqrstuvwxyz}$

No mess.Simple Gr.5 division.
Ah,I'm so relieved.