Centripetal force on a 2000 kg car rounding a 175 m curve at 50 km/h

[8parks11]

Calculate the centripetal force on a 2000-kg automobile roudning a curve of 175 m radius at a speed of 50 km/h.

ok
so this

Fc=mv^2/r
i did 2000(50)(1000)(3600) / 175

but this was incorrect. the answer is 2.2x10^3 N

the 1000x3600 was to convert the km/h to m/s and i think that's correct so what did i do wrong here.

 

[lotrgreengrapes7926]

The conversion is $$\frac{1}{1000}\frac{\text{km}}{\text{m}}$$, not $$1000\frac{\text{km}}{\text{m}}$$

 

[8parks11]

thx for pointing that out but.
i should be getting around 2200.

so i do

2000[(50)(.001)(3600)]^2 / 175
but i get 370285...
whats wrong here now?

 

[8parks11]

wait still... isn't 50km = 50000m?
so i should multiply 50x1000?

 

[8parks11]

iim keep getting 2057 if i use 0.01

 

[lotrgreengrapes7926]

Sorry, the hour to second conversion should be changed, not the km to meters.

 

[8parks11]

ok so if i do multiply 1000 or do "2000(50)(1000)(3600) / 175"
i don't get the answer 2.2x10^3 N
can you please help

 

[lotrgreengrapes7926]

ok so if i do multiply 1000 or do "2000(50)(1000)(3600) / 175"
i don't get the answer 2.2x10^3 N
can you please help

The 3600 hr/sec should be 1/3600. And remember to square. This will give an answer of about 2204.6.